Partial Fraction Decomposition
Decompose a rational function into partial fractions.
About Partial Fraction Decomposition
Partial fraction decomposition breaks a complex rational function into simpler fractions that are easier to integrate.
$$\frac{P(x)}{(x-a)(x-b)} = \frac{A}{x-a} + \frac{B}{x-b}$$
How to use this calculator
- Enter the rational function you want to decompose.
- Factor the denominator completely if it is not already factored.
- Check that the fraction is proper, meaning the degree of the numerator is less than the degree of the denominator.
- Read the decomposed form and use it to simplify your work.
The formula explained
For a fraction like \(\frac{P(x)}{(x-a)(x-b)}\), the goal is to write it as \(\frac{A}{x-a}+\frac{B}{x-b}\). The constants \(A\) and \(B\) are chosen so the two sides are equal for every allowed value of \(x\).
- x = the variable in the rational function
- P(x) = the numerator polynomial
- a = a value that makes one denominator factor zero
- b = another value that makes one denominator factor zero
- A = the constant coefficient of the first partial fraction
- B = the constant coefficient of the second partial fraction
Step by step method
- Factor the denominator completely, for example into terms like \((x-a)(x-b)\).
- Set up the partial fraction form with unknown constants, such as \(\frac{A}{x-a}+\frac{B}{x-b}\).
- Multiply both sides by the full denominator to clear fractions, then solve for the constants using substitution or matching coefficients.
Worked example
Problem. Decompose \(\frac{5x+1}{(x-2)(x+3)}\) into partial fractions.
- Write \(\frac{5x+1}{(x-2)(x+3)}=\frac{A}{x-2}+\frac{B}{x+3}\).
- Multiply by \((x-2)(x+3)\): \(5x+1=A(x+3)+B(x-2)\).
- Choose values that simplify the equation. If \(x=2\), then \(11=5A\), so \(A=\frac{11}{5}\). If \(x=-3\), then \(-14=-5B\), so \(B=\frac{14}{5}\).
Answer. \(\frac{5x+1}{(x-2)(x+3)}=\frac{11}{5(x-2)}+\frac{14}{5(x+3)}\)
Tips and common mistakes
- If the numerator degree is at least the denominator degree, divide first before decomposing.
- Always factor the denominator fully, because partial fractions depend on the individual factors.
Frequently asked questions
How do I use the partial fraction decomposition calculator?+
Enter the rational function with a polynomial numerator and a factored denominator. The calculator splits it into simpler fractions, then you can compare the result to the original expression to check your work.
What does the formula A/(x-a) + B/(x-b) mean?+
It means a rational function with denominator (x-a)(x-b) can be rewritten as two simpler fractions, one for each factor in the denominator. The unknown constants A and B are chosen so the two expressions are exactly equal.
What if the denominator has repeated factors or an irreducible quadratic?+
Then the decomposition has extra terms. A repeated factor like (x-a)^2 needs separate fractions for each power, and an irreducible quadratic needs a linear numerator, such as (Ax+B)/(x^2+1).
Can this calculator handle a numerator with higher degree than the denominator?+
Not directly as a partial fraction problem, because the rational function must be proper first. If the numerator degree is at least the denominator degree, you need polynomial long division before decomposing the remainder.
How do I interpret the result after decomposition?+
Each term shows a simpler component of the original rational function, which is useful for integration, inverse Laplace transforms, and simplifying algebra. If you combine the fractions back over a common denominator, you should recover the original expression.
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