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Pipe Sizing Calculator

Find pipe diameter for a flow at a target velocity.

Reviewed for accuracy by the Math Ora X team Last updated

Result

About the Pipe Sizing Calculator

Calculates the internal pipe diameter needed to carry a volumetric flow at a chosen velocity.

$$ d = \sqrt{\frac{4Q}{\pi v}} $$

How to use this calculator

  1. Enter the flow rate, usually in units like \(m^3/s\) or a matching unit for your setup.
  2. Enter the target velocity, usually in \(m/s\).
  3. Use the calculator to find the pipe diameter that fits that flow and speed.
  4. Check the result against your design limits, because real systems may need a standard pipe size next.

The formula explained

The formula calculates the pipe diameter needed for a given volumetric flow rate and flow velocity. It comes from rearranging the area relation \(Q = Av\), then using the circle area formula \(A = \\frac{\\pi d^2}{4}\).

  • d = pipe diameter
  • Q = volumetric flow rate
  • v = flow velocity
  • \(\\pi\) = the constant pi, approximately \(3.14159\)

Step by step method

  1. Start with \(Q = Av\), because flow rate equals cross-sectional area times velocity.
  2. Substitute the circular area formula \(A = \\frac{\\pi d^2}{4}\) into the equation.
  3. Rearrange to solve for \(d\), which gives \(d = \\sqrt{\\frac{4Q}{\\pi v}}\).

Worked example

Problem. Find the pipe diameter for a flow rate of \(0.02\\,m^3/s\) at a target velocity of \(2\\,m/s\).

  1. Use \(d = \\sqrt{\\frac{4Q}{\\pi v}}\).
  2. Substitute the values: \(d = \\sqrt{\\frac{4(0.02)}{\\pi(2)}}\). This gives \(d = \\sqrt{\\frac{0.08}{6.28318}}\).
  3. Compute the result: \(d \\approx \\sqrt{0.01273} \\approx 0.113\\,m\).

Answer. \(d \\approx 0.113\\,m\), or about \(113\\,mm\).

Tips and common mistakes

  • Make sure the units for \(Q\) and \(v\) are compatible, or the diameter will come out wrong.
  • If you need a real pipe, compare the calculated diameter with standard pipe sizes and choose the nearest practical option.

Frequently asked questions

What velocity is typical?+

Water supply ~1 to 2.5 m/s; too high causes noise and erosion.

Why not just use a big pipe?+

Larger pipes cost more and can run too slowly, allowing sediment.

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