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Ellipse Equation Calculator

Find properties of an ellipse from its equation.

Reviewed for accuracy by the Math Ora X team Last updated

Result

About Ellipse Equation Calculator

An ellipse has two foci. The sum of distances from any point on the ellipse to both foci equals 2a. Eccentricity 0 < e < 1.

$$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1$$

How to use this calculator

  1. Enter the ellipse equation in standard form.
  2. Identify the center coordinates from the shifted x and y terms.
  3. Compare the denominators to find the semi-axis lengths and the major axis direction.
  4. Use the calculator output to read the ellipse properties such as center, vertices, and foci.

The formula explained

$$ \frac{\left(x-h\right)^2}{a^2}+\frac{\left(y-k\right)^2}{b^2}=1 $$

  • \(x\) = the x-coordinate of a point on the ellipse
  • \(y\) = the y-coordinate of a point on the ellipse
  • \(h\) = the x-coordinate of the center
  • \(k\) = the y-coordinate of the center
  • \(a\) = the semi-axis length along the horizontal direction when the major axis is horizontal, or the larger semi-axis length in general form
  • \(b\) = the semi-axis length along the vertical direction when the major axis is horizontal, or the smaller semi-axis length in general form

Step by step method

  1. Rewrite the equation so the left side matches the standard ellipse form with a 1 on the right.
  2. Read the center directly from the shifts in x and y.
  3. Take the square roots of the denominators to get the semi-axis lengths.
  4. Use the larger denominator to decide whether the major axis is horizontal or vertical.
  5. Use the calculated values to identify the vertices, co-vertices, and foci.

Worked example

Suppose you want the properties of the ellipse given by \(\frac{(x-3)^2}{16}+\frac{(y+2)^2}{9}=1\).

  1. Match the equation to standard form. The center is \((3,-2)\) because the x term is \(x-3\) and the y term is \(y+2\).
  2. Find the semi-axis lengths: \(a=\sqrt{16}=4\) and \(b=\sqrt{9}=3\). Since 16 is larger than 9, the major axis is horizontal.
  3. Compute the focal distance using \(c^2=a^2-b^2=16-9=7\), so \(c=\sqrt{7}\).

Answer. Center: (3, -2), major axis horizontal, semi-major axis 4, semi-minor axis 3, foci: (3 - sqrt(7), -2) and (3 + sqrt(7), -2).

Tips and common mistakes

  • The larger denominator tells you the direction of the major axis.
  • Do not confuse the center shifts with the signs in the equation. x - h means the center x-coordinate is h, while y - k means the center y-coordinate is k.
  • Remember that the semi-axis lengths are the square roots of the denominators, not the denominators themselves.
  • If the equation is not already set equal to 1, simplify or divide first before using the calculator.

Frequently asked questions

What kind of equation does this calculator need?+

It works with an ellipse written in standard form. The equation should show the squared x and y terms divided by positive numbers and set equal to 1. If the equation is not in that form yet, rewrite it first.

What properties can I learn from the result?+

You can usually find the center, the lengths of the semi-axes, the direction of the major axis, and the locations of the vertices and foci. These are the main features that describe the ellipse.

How do I know if the major axis is horizontal or vertical?+

Look at which squared term has the larger denominator. If the x term has the larger denominator, the major axis is horizontal. If the y term has the larger denominator, the major axis is vertical.

Why is my answer not showing correctly?+

The most common issue is entering an equation that is not in standard form. Another common problem is using a negative denominator or forgetting to make the right side equal to 1. Check the format carefully before trying again.

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