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Freezing Point Depression Calculator

Calculate the freezing point depression of a solution.

Reviewed for accuracy by the Math Ora X team Last updated

Result

About Freezing Point Depression Calculator

Freezing point depression: adding solute lowers the freezing point. Salt on roads uses this principle. For water, Kf = 1.86 °C/m.

$$\Delta T_f = i K_f m$$

How to use this calculator

  1. Enter the van 't Hoff factor, which tells how many particles the solute makes in solution.
  2. Enter the freezing point depression constant for the solvent, written as \(K_f\).
  3. Enter the molality, \(m\), of the solution in \(\text{mol/kg}\).
  4. Read the freezing point change, then subtract it from the pure solvent's freezing point if you need the new freezing point.

The formula explained

The calculator uses \(\Delta T_f = iK_fm\) to compute the amount the freezing point is lowered. Here, \(\Delta T_f\) is the freezing point depression, not the final freezing point itself.

  • \(\Delta T_f\) = the freezing point depression, in degrees Celsius or Kelvin
  • i = the van 't Hoff factor, the number of particles formed per formula unit of solute
  • \(K_f\) = the freezing point depression constant of the solvent
  • m = the molality of the solution, in \(\text{mol/kg}\)

Step by step method

  1. Find \(i\), \(K_f\), and \(m\) for your solution.
  2. Multiply \(i\), \(K_f\), and \(m\) to get \(\Delta T_f\).
  3. If you want the new freezing point, subtract \(\Delta T_f\) from the pure solvent's freezing point.
  4. Check that your molality is in \(\text{mol/kg}\), because using molarity will give the wrong result.

Worked example

Problem. A solution has \(i = 2\), \(K_f = 1.86\,\degree C\cdot\text{kg/mol}\), and \(m = 0.50\,\text{mol/kg}\). Find the freezing point depression.

  1. Use the formula \(\Delta T_f = iK_fm\).
  2. Substitute the values: \(\Delta T_f = 2 \times 1.86 \times 0.50\).
  3. Compute the result: \(\Delta T_f = 1.86\,\degree C\).

Answer. The freezing point depression is \(1.86\,\degree C\).

Tips and common mistakes

  • Molality uses mass of solvent in \(\text{kg}\), not volume, so do not confuse it with molarity.
  • For electrolytes like \(\text{NaCl}\), the value of \(i\) may be close to \(2\), but real solutions can differ slightly.

Frequently asked questions

How do I use the freezing point depression calculator?+

Enter the van't Hoff factor, the solvent's freezing point depression constant Kf, and the molality of the solution. The calculator uses ΔTf = iKf m to find how much the freezing point drops below the pure solvent's freezing point.

What does the formula ΔTf = iKf m mean?+

ΔTf is the change in freezing point, i is the van't Hoff factor for how many particles the solute forms in solution, Kf is a property of the solvent, and m is molality in moles of solute per kilogram of solvent. A larger value for any of these inputs gives a bigger freezing point drop.

What units should I use for the inputs?+

Use molality in mol/kg, and Kf in degrees Celsius per molal or kelvin per molal, since a temperature change has the same size in °C and K. The result is a temperature decrease, usually reported in °C.

What happens if the solute does not dissociate?+

If the solute does not dissociate, use i = 1. For electrolytes like NaCl, i is greater than 1 because one formula unit can produce multiple particles in solution.

How is freezing point depression different from boiling point elevation?+

Both are colligative properties, so they depend on the number of dissolved particles rather than their identity. Freezing point depression tells you how much the freezing point goes down, while boiling point elevation tells you how much the boiling point goes up.

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